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General physics
Solution8. Worked Examples
📐 Worked Examples

Example: Node Measurement

On a 1 m string in 4th harmonic, nodes are observed at x = 0, 0.25, 0.50, 0.75, 1.00 m. Find λ.

Node positions

1. Learning Objectives2. Language Objectives3. Key Terms3.1. Study Cards4. Glossary5. Theory6. Memorization Exercises7. Video Lesson
🎯 Learning Objectives
  • Determine wavelength from node or antinode spacing in a stationary wave
  • Relate distance between adjacent nodes (or antinodes) to half a wavelength
  • Apply node/antinode measurements to experimental setups (strings, air columns)
  • Explain how to measure λ in different harmonic modes
🗣️ Language Objectives
  • Use terms “node spacing,” “antinode spacing,” “half-wavelength,” “harmonic” accurately
  • Describe measurement procedures clearly in English
  • Interpret instructions and report results with correct terminology
  • Discuss experimental uncertainty and precision in academic language
📚 Key Terms and Translations
English TermRussianKazakh
Wavelength (λ)Длина волны (λ)Толқын ұзындығы (λ)
Node spacingРасстояние между узламиТоқтау нүктелері арасындағы қашықтық
Antinode spacingРасстояние между пучностямиМаксимум нүктелері арасындағы қашықтық
HarmonicГармоникаГармоника
Fundamental modeОсновной режимНегізгі режим
🃏 Vocabulary Study Cards

Node Spacing

Definition: Distance between two adjacent nodes = λ/2

Use: Measure to find λ

Antinode Spacing

Definition: Distance between adjacent antinodes = λ/2

Harmonic

Definition: A resonant mode with n half‐wavelengths fitting in the medium

📖 Glossary of Terms

Wavelength (λ)

Distance over which the wave’s shape repeats; in stationary wave, λ = 2·(node spacing).

Translation
Russian: Расстояние, через которое форма волны повторяется; в стоячей волне λ = 2·расстояние между узлами.
Kazakh: Толқын формасы қайталанатын қашықтық; тұрақты толқында λ = 2·тоқтау нүктелері арасындағы қашықтық.
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Harmonic

An integer multiple of the fundamental frequency; n-th harmonic has n·(λ/2) segments.

Translation
Russian: Целочисленное кратное основной частоте; n-ая гармоника содержит n·(λ/2) сегментов.
Kazakh: Негізгі жиіліктің бүтін еселігі; n-ші гармоника n·(λ/2) сегменттен тұрады.
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🔬 Theory: Determining Wavelength from Nodes/Antinodes

In a stationary wave, adjacent nodes (or antinodes) are separated by <su_tooltip text="половина длины волны/толқын ұзындығының жартысы" behavior="click"]λ/2[/su_tooltip]. Thus:

  • Measure distance Δx between two adjacent nodes → λ = 2·Δx
  • For n nodes spanning distance L: L = (n–1)·(λ/2) → λ = 2L/(n–1)
  • In the n-th harmonic on a string of length L: λ = 2L/n
Translation
Russian: В стоячей волне расстояние между соседними узлами равно λ/2, поэтому λ = 2·Δx. Если на длине L между первым и n-тым узлом n–1 промежуток, λ = 2L/(n–1).
Kazakh: Тұрақты толқында жақын тоқтау нүктелері арасындағы қашықтық λ/2-ге тең, сондықтан λ = 2·Δx. L ұзындықта n-ші тоқтау нүктесіне дейін (n–1) аралық болса, λ = 2L/(n–1).
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Theory Questions

Easy: If adjacent nodes are 0.25 m apart, what is λ?
Answer
λ = 2·0.25 m = 0.50 m.
Medium: A string of length 0.8 m shows 5 nodes (including ends). Calculate λ.
Answer
Number of intervals = 4; L = 4·(λ/2) → λ = 2·L/4 = 0.40 m.
Medium: In 3rd harmonic on a 1.2 m wire, what is λ?
Answer
λ = 2L/3 = 2·1.2/3 = 0.80 m.
Hard (Critical Thinking): Discuss sources of error when measuring node spacing in a real experiment.
Answer
Errors from finite node width, instrument resolution, tension variations, and environmental damping can shift apparent positions.
💪 Memorization Exercises

Fill in the Blanks

  1. Distance between adjacent nodes = ______.
  2. λ in terms of node spacing Δx: λ = ______.
  3. For n intervals in length L, λ = ______.
  4. In the fundamental mode (n=1), λ = ______.

Answer
1. λ/2
2. 2·Δx
3. 2L/n
4. 2L
Answer
Node spacing = 0.25 m = λ/2 → λ = 0.50 m.
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